L\u00f4 c\u00e2m l\u00e0 g\u00ec?<\/h2>\n
L\u00f4 c\u00e2m<\/strong> l\u00e0 con l\u00f4 kh\u00f4ng v\u1ec1 \u2013 xu\u1ea5t hi\u1ec7n trong b\u1ea3ng k\u1ebft qu\u1ea3 c\u1ee7a k\u1ef3 m\u1edf th\u01b0\u1edfng h\u00f4m \u0111\u00f3. H\u00e0ng ch\u1ee5c kh\u00f4ng v\u1ec1 th\u00ec l\u00e0 l\u00f4 c\u00e2m \u0111\u1ea7u<\/strong>, h\u00e0ng \u0111\u01a1n v\u1ecb kh\u00f4ng v\u1ec1 l\u00e0 l\u00f4 c\u00e2m \u0111u\u00f4i (l\u00f4 \u0111\u00edt c\u00e2m)<\/strong>.<\/p>\n